Oh, I misread as two of them being accurate (only 1 being inaccurate).
Ogre-princess-brother:
1. If the ogre was telling the truth about eating over 100 humans, then the brother would also be correct about definitely more than one. If the ogre is wrong and the brother is accurate, than the princess would also be accurate. Therefore the princess must be accurate, and the number must be 0 or 1. So I am going with 1.
Man dies in a house:
An outdoorsman
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The correct number of people consumed by said ogre is zero. COMaestro and bruitist basically got it. If it’s more than 100 (Ogre) then the brother is also telling the truth. If it’s more than 1 then either the ogre or princess are correct. If it’s less than 100, then the Princess is correct and if it’s less than 1 then the brother is also wrong. I think the original wording was the brother saying “Surly it’s at least one!”, or something like that, but it sounds too obvious to me. Anyway. Yes, either 0 or 1 is correct, but it’s supposed to be zero
The answer to the second one is silly, but I like it: The correct answer is ‘ton’. Heavy when written forward, ‘not’ when written backwards. Har har.
The answer to the third one is also silly: a snowman. I mean, technically you could argue that it could be a very cold house (don’t say an igloo, they’re notoriously warm), but it idea still holds.
And as already solved, a hole gets bigger the more you take away.
Only if warm things are inside them!
And I should have gotten the ton one. That’s the kind of nonsense I thrive on!
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I know of a few houses in NZ where that snowman could survive, easily…
This one being either one or zero is doing my head: cannot be zero, or the princess would be wrong as well…?
Love that one, but I was late to guess.
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I got one and two, was still noodling on three and four when I saw more clever people had nailed them.
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Would adventures work? Add an s and its adventuress? As in a female adventurer?
Ah, it’s clever but I can’t find it in the dictionary.
Revisiting ye olde BBs.
Framing. Not a spoiler, but helpful handles for thinking through it:
BBs can be in four designations:
U = Unknown
S = Confirmed Standard
L = Possibly Light
H = Possibly Heavy
Imagine four bowls, all 12 start in the U bowl. Your job is to get 11 to the S bowl so only one remains in either the L or H.
Also worth noting, a BB can move from the U bowl to any bowl, and from the H or L bowls to the S bowl. But once a BB is in the H bowl, it can never move to the L bowl, or vice versa.
The first weighing, mild spoiler. More for narrowing the decision space than spoiling the puzzle:
4U vs 4U
And afterwards, you’ll either have 8S + 4U, or 4S + 4H + 4L
The second weighing is the crux of the problem and where the make or break insight is needed.
Even though we’re constantly passing through time, sometimes it can be difficult to think about the way time flows.
If yesterday’s day after tomorrow is Sunday, what day is tomorrow’s day before yesterday?
If seven days after 70 days ago was a Sunday, seven days before 70 days from today is what day of the week?
A doctor needs to visit nine different hospital rooms. After studying the room numbers, she notices that she can visit all the rooms in one round. In order to do so, she must go into a room that has at least one shared digit with the room she is currently in.
Using this method, which room will she visit fifth? Rooms are arrayed as below:
18 - 38 - 63
29 - 49 - 65
33 - 54 -71
(The arrangement of the rooms has no impact on the puzzle)
Okay, last one:
Three people played Memory with 20 total cards of 10 pairs.
Person A said “I matched ten pairs in a row from the start.”
Person B said “I matched nine pairs in a row from the start.”
Person C said "I matched eight pairs in a row from the start.
One person is a liar. Which one?
(These riddles all brought to you by the latest “Professor Layton.” There are lots more, if people are interested! And if you do post a solution, spoiler it out so anyone else can keep going.)
Oh, and if you want a hint for any of them, let me know!
EDIT: Fixed one of the puzzles to remove a misunderstanding on my part.
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Friday
Sunday…?
I feel like I’ve missed a trick somewhere
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Memory Game
the person claiming to have matched 9 pairs is lying. After matching 9 pairs, there would only be 1 pair left and it would be impossible not to match them.
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Healthcare globally is in enough of a state as it is without these bullshit restrictions!!! 
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OK, but there is nothing in the description indicating that adjacency matters. In fact, if she could only move to adjacent rooms, rooms 71 and 33 break the digit rule. So why is the diagram necessary, aside from obfuscating the relationship of numbers?
71 only “connects” to 18. From there, 38 is the only choice…
71 18 38 33 63 65 54 49 29
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You are correct. You can visit any of the rooms regardless of proximity.
My bad on that one. I misunderstood the initial conditions of the puzzle.
I think I finally figured this out when I was having trouble sleeping last night.
By the third weighing you need to have at most three bb’s unidentified if you know whether they are heavier or lighter, or one bb if you don’t know whether it is heavier or lighter.
I found the 8S + 4U case easier: weigh 3U against 3S, which leaves you with either 11S and 1U (scales balanced) or 3H/L and 9S (scales tipped left/right).
With 1U you simply measure against 1S to find if it is heavier or lighter. With 3H you measure 1H against 1H and whichever bb is on the lower side is the rogue heavier bb.
If the scales are balanced then the unweighed bb is the rogue heavier bb.
Exactly the same for the 3L case, but the bb on the higher side is the rogue lighter bb in the third measurement.
For the 4S + 4H + 4L case: the goal is to get to at most three H or L bb’s after the second measurement.
Weigh 2H + 2L against 1H + 1L + 2S.
If the scale tips to the left then we have 9S + 2H + 1L. Weigh 1H vs 1H, which either identifies the heavy bb or, if the scales are level, tells you that the unweighed bb is light.
Same if the scale tips to the right, but with all H’s and L’s swapped.
If the scale is level in the second measurement then we have 10S + 1H + 1L. Weigh 1H vs 1S. If the scale tips left then that is the rogue heavy bb or, if the scales are level, then the unweighed bb is the rogue light bb.
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Yes! BUT, and this is the clever bit, you could also start from 29… and get exactly the same conclusion, traveling the path in reverse. Same answer either way, though! Thanks for the catch on the faulty starting conditions of the puzzle. I have corrected my initial post.
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I caught that immediately when they asked for the 5th door, since that would have been in the middle of 9, so it didn’t matter which direction you went. It is just a means to remove the inherent ambiguity of the two possible answers. I figured that out before figuring out the answer.
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Re: BB’s.
That nails it. My solution is slightly different:
Second weighing, after 4H, 4L, 4S:
HHL vs HHL
If they are even, you have a new 6S and are only left with 2L for the third weighing.
If they are uneven, you have 2H from the side that went down and 1L from the side that went up, regardless of which side drops. You can easily parse those with a final weighing of the 2H.
The key to any solution is putting H and L on the same side of the scale because you get additional insight for level, up, or down that way (compared to having all H or L, which doesn’t tell you anything if it goes in the same direction you already coded.)
Re: Memory puzzle.
Oh, is that it? I thought they were playing competitively against each other and couldn’t find a way two of them could be right.
@Marx I enjoyed the other three though I won’t repeat answers that others have already confirmed! I played the Puzzle Agent series which is supposed to be based on Layton, and loved it.
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